Arrange the following carbanions in decreasing order of stability. Consider the following carbanions.

Arrange the following carbanions in decreasing order of stability Step 4: Draw conclusions about the relative stability of the carbon anion in each molecule. Read all about it under one roof. I. Generally, carbanions are stabilized by resonance and destabilized by electronegative atoms. Arrange the following intermediate into decreasing order of stability. Electron withdrawing substituent increases the stability of carbanion and electron-donating substituent decreases the stability of carbanion. Arrange the following carbocations in decreasing order of stability. Hence, option D is correct because decreasing order of stability III > I > II > IV Note: We have to remember that the inductive effect, electromeric effect, resonance or mesomeric effect and hyper conjugate effect play an important role for electron displacement. Arrange the following carbanions in decreasing order of stability: `underset ( (I)) (. The rate of SN1 reactions are governed by the stability of carbocation whereas for SN2 reactions steric factor is the deciding factor. (A) H_3C-C≡C^- (B) H-C≡C A carbanion is a negatively charged electronrich species in which the carbon atom is trivalent and has an unshared pair of electrons So any factor that will decrease Problem 11 Multiple Choice Sort the following species in decreasing order of stability. The order of decreasing stability for the given carbanions, considering these effects, is II > I > III. H3 C−CH2 So the correct order of decreasing stability of carbanion is C C l 3> C 6 H 5 C H 2> (C H 3) 3 C H> (C H 3) 2 C Thus the correct option is (C). I) CH 3 −CH − 2 II) CH 2 = CH − III) CH ≡ − C Correct order of stability of these carbanions in decreasing order is: Further we must know that the stability order decreases as we move from the primary to the tertiary anion because due to +I effect of the methyl groups as there is an increased intensity of negative charge on the central carbon of the tertiary carbanion which further makes it unstable. H−C≡C− C. Consider the following carbanions. ly/PW_APP 🌐PW Consider the following carbanions. + I effect is maximum in (CH 3) 3 C −, followed by (CH 3) 2 CH − and C H 3 C H 2 −. Less electronegative (25 -character) More the s -character of charged carbons, greater will be the stability. Inductive effect is a permanent effect. Click here👆to get an answer to your question ️ Arrange the following carbanions in order of stability. A) H_ (3)C-C-=C^ (-) B) H-C-=C^ (-) C) H_ (3)C-Cbar (H)_ (2) by Chemistry experts to help you in doubts & scoring excellent marks in Class 12 exams. Nov 23, 2022 · Arrange the following carbanions in decreasing order of stability : ⊖CH2−Cl⊖CH2−CN⊖CH2−NO2∘CH2−CH3 (I) (II) (III) (IV) 13 mins ago Discuss this question LIVE 13 mins ago One destination to cover all your homework and assignment needs Learn Practice Revision Succeed Instant 1:1 help, 24x7 60, 000+ Expert tutors Textbook solutions A carbanion is a negatively charged electronrich species in which the carbon atom is trivalent and has an unshared pair of electrons So any factor that will decrease Arrange the following carbanions in order of their decreasing stability: A. View Solution Arrange the following compounds in decreasing order of their reactivity with sodium methoxide in methanol at 50∘ C. Inductive effects: Electron-withdrawing groups stabilize the carbanion. Whatever mechanism alkyl halides follow for the substitution reaction to occur, the polarity of the carbon halogen bond is responsible for these substitution reactions. Related Solutions Arrange the following carbanions in order of their decreasing stability. In C 6 H 5 C H 2 −, resonance effect increases the stability. H−C≡C−C. ^ (Theta) (CH_ (2))-Cl)` , `underset ( (II)) (. H3C−C≡C− B. +I effect is maximum in (C H 3)3C −, followed by (C H 3)2C H − and C H 3C H 2−. Factors influencing stability include: Resonance stabilization: Carbanions adjacent to groups that can delocalize the negative charge (like phenyl or vinyl groups) are more stable. Ask your next question Or Upload the image of your question Get Solution Found 7 tutors discussing this question Ava Discussed Arrange the following carbanions in order of their decreasing stability: A. ABC b. Additional Information Download Solution PDF Share on To arrange the given carbanions in order of their decreasing stability, we have to consider factors such as the inductive effect, resonance stabilization, and hybridization. Step 3/5Evaluate each carbanion based on the factors identified in step 2. Conclusion: Thus, the order of their decreasing stability of given carbanions is B > A > C. AnswerWrite down the final list of sp-Hybridized carbon is more electronegative than a sp^3-hybridized carbon and hence can accommodate the negative charge better. Jul 31, 2022 · Arrange the following carbanions in order of their decreasing stability : (A) H_3C-C≡C^- (B) H-C≡C^- (C) H_3C-CH_2^- (a) ABC (b) BAC (c) CBA (d) CAB 📲PW App Link - https://bit. More electronegative (50%s -character) No +I -effect to destabilise the carbanion. A) H 3 C C ≡ C B) H C ≡ C C) H 3 C C H 2 View Solution Among a,b,c and d q will be most stable and d will be least stable because in negative charge is kept on Sp2 hybridised carbon but in d negative charge is kept on Sp3 hybridized carbon atom. View Solution Click here👆to get an answer to your question ️ Arrange the following carbanions in increasing order of their stability. (v) Arrange the primary, secondary and tertiary alcohols into decreasing order of acidity . H_3C-CH_2 a. Carbanion (S): This is a cyclic carbanion with resonance stabilization Step 3: Compare the stability of the carbon anion in each molecule based on the effect of the substituent groups. ly/PW_APP Arrange the following carbanions in decreasing order of stability: (A) | II I IV II (B) III II I IV (C) ||||||| V (D) ||||||| V📲PW App Link - https://bit. – CH 3 group has +1 effect, therefore, it intensifies the negative charge Objectives After completing this section, you should be able to describe the geometry of a given carbocation. Arrange following carbanions in decreasing order of stability : (i) [C-]C(Cl)CC [C-]C(C=N)CC [C-]C(F)CC (P) (R) Arrange the following compounds in the order of decreasing acidity. Apr 26, 2020 · Arrange the following carbanions in decreasing order of stability: `CH_ (2)underset ( (P)) Mar 19, 2024 · The correct order of decreasing stability for the given carbanions, based on inductive effects and hybridization, is II > I > III, with the absence of alkyl groups and a higher s-character leading to greater stability. The dissociation enthalpies are much lower in solution because polar solvents can stabilize the ions, but the order of carbocations stability remains the same. (1) III I IV II (2) III II I IV (3) I III II IV (4) III I II IV📲PW A Arrange the following free radicals in order of decreasing stability: Methyl I, Vinyl II, Allyl III and benzyl (IV) Jul 21, 2023 · Step by step video solution for Arrange the following carbanions in decreasing order of stability : <BR> (I) CH_ (2)^ (-)-Cl<BR> (II)CH_ (2)^ (-)-CN<BR> (III)CH_ (2 The stability of carbanions in the following i) RC ≡ ⊖ C ii) iii) R2C = ⊖ CH iv) R3C− ⊖ CH 2 is in the order of Thus, the decreasing order of stability of carbanion is as follows: Thus, the correct option is C. So, correct order of stability : a>b>c>d. +I effect is also present in A, but there is more distant from negatively charged carbon, and in B there is no +I effect. II. `III gt II gt II gt IV` D. In the given question, the compounds differ in the number of bonds to which the carbanion is attached, i. Solution: More electronegative (50%s -character) +I -effect of —C H 3 group destabilises the carbanion. Therefore, B is more stable than C. Option (b): Stability of carbanions decreases with increase in + I effect. B > A > C Explanation: The order of decreasing stability of carbanions is: H − C ≡ C 𝐴 − (B)> C H 𝐴 3 − C ≡ C 𝐴 − (A)> C H 𝐴 3 − C H 𝐴 − (C) sp-hybridised carbon atom is more electronegative than sp3-hybridised carbon atom and hence, can accommodate the negative charge more effectively. Nov 27, 2022 · Solution For Arrange the following carbanions in order of their decreasing stability. I II III IV View Solution Click here👆to get an answer to your question ️ consider the following carbanionsich3ch2 iich2chiiichequiv oversetccorrect order of stability of these carbanions Jul 21, 2023 · Step by step video & image solution for Arrange the following carbanions in increasing order of stability: by Chemistry experts to help you in doubts & scoring excellent marks in Class 11 exams. Step 1/5Identify the carbanions in the list provided. IV. H3C−CH2− (1) A > B > C (2) B > A > C (3) C > B > A (4) C > A > B 5 mins ago Discuss this question LIVE 5 mins ago One destination to cover all your Now the distance between electronegative O atom and negative charge is in order :1 <2 <3. The substitution reaction of alkyl halide mainly occurs by S N 1 or S N 2 mechanism. As distance between them increases the stability of carbanion decreases. I… Oct 24, 2024 · Solution For Arrange the following carbanions in decreasing order of stability: (i) CH≡C−π (ii) CH2 =CH (iii) CH3 −C¨H2 Arrange the following carbanions in order of their decreasing stability. Arrange the following carbanions in decreasing order of stability: `""^ (Ө)underset (" " (I)) (CH_ (2))-Cl " """^ (Ө)underset (" " (II)) (CH_ (2))-CN" . Therefore, (A) and (B) are more stable than (C ). (I) H 3C −C ≡ C− (II) H −C ≡ C− (III) H 3C −CH − 2 View Solution Q 2 - Therefore the increasing order of the stability of the given carbanions is as follows. Class: 12 Subject: CHEMISTRY Chapter: JEE MAINS 2022 Board:IIT JEE You can ask any doubt from class 6-12, JEE, NEET, Teaching Arrange the following carbanions in order of their decreasing stability. 1. Apr 7, 2025 · Correct option is : (2) (A) > (C) > (B) > (D) (A) is most stable as it is stabilised by resonance as well hyperconjugation due to two \ (\alpha\)-hydrogen atoms. If the Jan 2, 2025 · 97 Share Report Ask your next question Or Upload the image of your question Get Solution Found 8 tutors discussing this question Charlotte Discussed Arrange the following carbanions in decreasing order of stability : [C-]c1ccccc1 [C+]c1ccc (C)cc1 [C-]c1ccc ( [N+] (=O) [O-])cc1 [C-]c1ccc (OC)cc1 I II III IV III > I > IV > II III > II > I > IV I > III > II > IV III > I > II > IV 5 mins ago Jun 30, 2023 · Solution For - Carbanion Stability 4. Again b is more stable than c because in b electron Π cloud is delocalized between 6 atom. Arrange the following carbanions in decreasing order of stability: View Solution I. H3 C−C≡C−B. III. Carbanions are more stable when the negative charge is delocalized or stabilized by electron-withdrawing groups. Additionally, electron-withdrawing groups stabilize carbanions through inductive effects, while electron-donating groups destabilize them. Arrange the following carbanions in decreasing order of stability: Apr 27, 2025 · Stability order of carbanions decreases as we move from primary to tertiary anion because due to +I effect of methyl groups there is an increased intensity of negative charge on central carbon of tertiary carbanion which further makes it unstable. e. Since CH3 group has +I -effect, therefore , it intensifies the negative charge and hence destabilizes A relative to B. `III gt I gt II gt IV` Arrange the following carbanions in order of their decreasing stability. Stability of Carbanions The stability of carbanions depends on the ability to delocalize or accommodate the negative charge. ¯¯¯¯C Cl3> C6H5¯¯¯¯C H2> (CH3)2¯¯¯¯C H>(CH3)3¯¯¯¯C Stability of carbanion orders is a concept in organic chemistry that is arranged in the manner of substituted carbocations. A. a) I > II > III > IV b) II > IV > III > I c) II > I > IV > III d) II > I > III > IV View Answer c : The groups having +I effect decrease the stability while groups having –I effect increase the stability of carbanions. −CH3 group has +I effect, therefore, it intensifies the negative charge and hence, destabilises the carbanion . Note: Stability of carbanion by resonance effect is due to the presence of lone pairs of electrons and their involvement with delocalization of electrons ( pi electrons). having +Meffect. CAB 📲PW App Link - https://bit. Step 1: Identify the Carbanions The carbanions given are: A) H3C −C ≡ C− (Carbanion A) B) H −C ≡ C− (Carbanion B) C) H3C −C−(H)2 (Carbanion C) Step 2: Determine the Hybridization 1. I) CH 3 −CH − 2 II) CH 2 = CH − III) CH ≡ − C Correct order of stability of these carbanions in decreasing order is: Jul 21, 2023 · Step by step video, text & image solution for Arrange the following carbanions in decreasing order of stability: by Chemistry experts to help you in doubts & scoring excellent marks in Class 11 exams. The stability of the carbanions will increase by the presence of electron withdrawing groups. Hyperconjugation To determine the stability of the given carbanions, we will analyze the hybridization of the carbon atoms and the effects of substituents on their stability. Concepts: Carbanion stability, Resonance, Inductive effect Explanation: To determine the stability of carbanions, we consider factors such as resonance stabilization and inductive effects. Also, out of 2° and 3° carbanions, 2° carbanions are more stable, thus the decreasing order of stability is : Arrange the following carbanions in decreasing order of stability:PI. Note: The stability of carbanion is dependent on the nature and position of the substituent. H_3C-C≡C^- B. Carbanion follow stability order. Apr 13, 2025 · Concepts: Carbanion stability, Resonance, Inductive effect Explanation: To determine the stability of the carbanions, we need to consider the effects of substituents on the stability of the carbanion. Carbanion A (H3C − Arrange the following carbanions in decreasing order of their stability? (I) [C-]c1ccc (C)cc1 (II) [C-]c1ccc (OC)cc1 (III) [C-]c1ccc (C#N)cc1 (IV) [C-]c1ccc ( [N+] (=O) [O-])cc1 (1) I > III > II > IV (2) III > IV > II > I (3) IV > III > I > II (4) II > I > III > IV 15 mins ago Discuss this question LIVE 15 mins ago One destination to cover all your homework and assignment needs Learn Practice Stability of the carbanions depends upon several factors. Carbanions that can delocalize their negative charge through resonance or are stabilized by electron-withdrawing groups are more stable. Note: If there is a presence of any electron donating groups (+I effect) in carbanions then the carbanions are more unstable than the normal carbanions. Identify the Carbanions: - (I) (CH3)3C− - Tertiary carbanion - (II) (CH3)2CH− - Secondary carbanion - (III) CH3CH− 2 - Primary carbanion - (IV) C6H5CH− 2 - Benzyl carbanion 2 Click here:point_up_2:to get an answer to your question :writing_hand:arrange the following carbanions in decreasing order of stability This article will deliver comprehensive knowledge with certain examples of the stability of carbanions in the following piece, along with a few examples asking you to arrange the following carbanions in decreasing order of stability. arrange a given series of carbocations in order of increasing or decreasing stability. II. 3° carbocation is stabilized by the inductive effect of the alkyl groups. The resonance energy of a compound is the difference in energy between the most stable resonance structure and the contributing resonance structures. The order of decreasing stability of carbanions is: sp -hybridised carbon atom is more electronegative than sp3 -hybridised carbon atom and hence, can accommodate the negative charge more effectively. Inductive effect is inversely proportional to the distance distance increases (iv) Arrange the primary, secondary and tertiary alcohols into decreasing order of reactivity towards sodium. Also out of 2° and 3° carbanions 2° carbanions are more stable thus the decreasing order of stability is : Step by step video, text & image solution for Arrange the following carbanions in order of their decreasing stability. Therefore, the correct option is b. (I) H 3C −C ≡ C− (II) H −C ≡ C− (III) H 3C −CH − 2 However, it does not have any adjacent C-C or C-H sigma bonds for hyperconjugation. To determine the stability of the given carbanions, we will analyze each one based on their hybridization and the effect of substituents on the stability of the negative charge. carbanion I has a single bond, II has a double bond and III has a triple bond. Arrange the following carbanions in decreasing order of their stability оY I II III I (2) III &amp;amp;gt; I &amp;amp;… Get the answers you need, now! <p>To arrange the given carbanions in order of their decreasing stability, we need to analyze the hybridization and the effects of substituents on the stability of the negative charge. Hence, the correct decreasing order of stability is (ii)> (i)> (iii). (I) H3C - C C^ - (II) H - C C^ - (III) H3C - CH^ - 2 A. Thus, the overall stability decreases in the order : B gt A gt C Consider the following carbanions. To determine the order of decreasing stability of the given carbanions, we need to analyze the structure and stability of each carbanion based on the degree of substitution and the presence of resonance. (C Jul 21, 2023 · Step by step video, text & image solution for Arrange the following carbanions in order of their decreasing stability. Here is the analysis for each carbanion: Carbanion (P): The carbanion is adjacent to a methoxy group Apr 11, 2023 · Found 5 tutors discussing this question Noah Discussed Arrange the following carbanions in the increasing order of stability 8 mins ago Discuss this question LIVE Question Consider the following carbanions and arrange the decreasing order of their stability A II>III>IV>I B The stability of carbanion depends on various electronic effectsie inductive effect resonance and hyperconjugation effect of various groups or atoms attached to them Stability of carbanions decreases with increase in +I effect. Explain the stability of 3°, 2° and 1° carbocation and arrange them in decreasing order of their stability. (1) III I IV II (2) III II I IV (3) I III II IV (4) III I II IV📲PW A The order of decreasing stability of carbons is: H− C ≡ C− (I)> CH3 − C ≡ C− (I)> CH3− CH− 2 (III) sp-hybridised carbon atom is more electronegative than sp3-hybridised carbon atom annd hence, can accomodate the negative charge more effectively. ^ (Theta) (CH_ (2))-CN Oct 26, 2021 · Correct Answer - B The order of decreasing stability of carbons is: H − C ≡ C − (I)> C H 3 − C ≡ C − (I)> C H 3 − C H − 2 (I I I) H - C ≡ C - (I)> C H 3 - C ≡ C - (I)> C H 3 - C H 2 - (I I I) sp-hybridised carbon atom is more electronegative than sp3 s p 3 -hybridised carbon atom annd hence, can accomodate the negative charge more effectively. Since the -CH3, group has a + I effect, it intensifies the negative charge and therefore, destabilizes A as compared to B. Arrange the carbanions, (CH_3)_3C, CCl_3, (CH_3)_2CH, C_6H_5CH_2in order of their decreasing stability: (a) (CH_3)_2CHCCl_3C_6H_5CH_2 (CH_3)_3C (b) CCl_3C_6H_ Arrange the following carbanions in order of their decreasing stability. In C 6H 5C H 2−, resonance effect increases the stability. Apr 3, 2018 · (c) : The groups having +I effect decrease the stability while groups having –I effect increase the stability of carbanions. Thus, the order of stability is: B>A>C. BAC c. Step 4/5Arrange the carbanions in decreasing order of stability based on the evaluation in step 3. 7. Carbanions that can delocalize their negative charge through resonance are generally more stable. explain the relative stability of methyl, primary, secondary and tertiary carbocations in terms of hyperconjugation and inductive effects. (A) H_ (3)C-C -=C^ (-) (B) H-C-=C^ (-) (C) H_ (3)C–CH_ (2)^ (-)Class: 11Subject: CHEMISTRY Oct 15, 2021 · The 21. Based on the analysis above, we can arrange the carbanions in order of decreasing stability as follows:B > A > CTherefore, the correct answer is option 'B', which states that carbanion B is the most stable, followed by carbanion A, and then carbanion C. CBA d. Carbanions are more stable when they are able to delocalize the negative charge through resonance or when they are attached to electron-withdrawing groups that stabilize the negative charge through inductive effects. ) III I II IV📲PW App Li Oct 24, 2018 · Arrange, the carbanions, (CH3)3 C, CCl3, (CH3)2 CH, C6H5 CH2 In order of their decreasing stability The stability of carbanions depends on several factors such as resonance, inductive effect, and hybridization. 3° carbocation is the most stable carbocation compared to 2° and 1° carbocation. Due to the −I effect of three chlorine atoms and due to pπ−dπ bonding CCl− 3 is extra stable. III. Nov 27, 2022 · Solution For Arrange the following carbanions in decreasing order of stability. −C H 3 - C H 3 group has +I International Baccalaureate Chemistry Arrange the following carbanions in decreasing order of stabil Question Question asked by Filo student Arrange the following carbanions in decreasing order of stability : Arrange the following carbanions in decreasing order of stability:PI. IV. In this case, we analyze the given Explanation: CH 3 group has +I effect, which decreases the stability of carbon anion and in C this effect direct to negatively charged carbon. Benzyl carbanion is stabilized due to resonance. Stability and Reactivity of Carbocations The stability relationship is fundamental to understanding many aspects of reactivity and especially if it concerns nucleophilic substituents. Jul 31, 2022 · Arrange the following carbanions in decreasing order of stability : (a) PQRS (Q) (R) (S) (c) SQRP Mar 18, 2023 · Find an answer to your question Arrange the following carbanions in order of their decreasing stability. A) H 3 C - C ≡ C - B) H - C ≡ C - C) H 3 C - C H ¯ 2 View Solution Explanation: To determine the stability of carbanions, we consider factors such as resonance and inductive effects. I) CH 3 −CH − 2 II) CH 2 = CH − III) CH ≡ − C Correct order of stability of these carbanions in decreasing order is: Apr 20, 2022 · Arrange the following carbanions in decreasing order of stability: A. H-C≡C^- C. Sure, here are the step-by-step solutions: To determine the stability of the given compounds, we need to calculate their resonance energies. The stability of carbanions in the following i) RC ≡ ⊖ C ii) iii) R2C = ⊖ CH iv) R3C− ⊖ CH 2 is in the order of Arrange the following carbanions in decreasing orderof stability:IIIIIIIV(1) III I IV II(2) III II I IV(3) I III II IV(4. `III gt I gt IV gt II` B. Withdrawing or donating the electron density of the carbon atom by the Apr 13, 2025 · Concepts: Carbanion stability, Resonance, Inductive effect, Hyperconjugation Explanation: The stability of carbanions depends on factors such as resonance stabilization, inductive effects, and hyperconjugation. For carbanions, the stability typically increases with the amount of s-character in the hybrid orbitals that host the lone pair of electrons. Step 2/5Determine the factors that contribute to the stability of carbanions, such as resonance, inductive effects, and hybridization. Step by Step Solution Click here:point_up_2:to get an answer to your question :writing_hand:arrange the carbanions ch33 ccl3cch32hcc6h5h2c in order of their decreasing stability Arrange the following carbanions in order of their decreasing stability. The stability of carbanions depends on the ability to delocalize the negative charge and is influenced by hybridization and substituents. bkkk yyd nfjc cojrad dyws wkpdqsf nsqed cjjoxpq xqkvki bxmiiz euilvk suaw god hubki dfpxx